Optimal. Leaf size=183 \[ -\frac{2 \sqrt{2 \pi } e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{3 b^{5/2} c^2}+\frac{2 \sqrt{2 \pi } e^{-\frac{2 a}{b}} \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{3 b^{5/2} c^2}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{2 x \sqrt{c^2 x^2+1}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}} \]
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Rubi [A] time = 0.517266, antiderivative size = 183, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 10, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.714, Rules used = {5667, 5774, 5669, 5448, 12, 3308, 2180, 2204, 2205, 5675} \[ -\frac{2 \sqrt{2 \pi } e^{\frac{2 a}{b}} \text{Erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{3 b^{5/2} c^2}+\frac{2 \sqrt{2 \pi } e^{-\frac{2 a}{b}} \text{Erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{3 b^{5/2} c^2}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{2 x \sqrt{c^2 x^2+1}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}} \]
Antiderivative was successfully verified.
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Rule 5667
Rule 5774
Rule 5669
Rule 5448
Rule 12
Rule 3308
Rule 2180
Rule 2204
Rule 2205
Rule 5675
Rubi steps
\begin{align*} \int \frac{x}{\left (a+b \sinh ^{-1}(c x)\right )^{5/2}} \, dx &=-\frac{2 x \sqrt{1+c^2 x^2}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}+\frac{2 \int \frac{1}{\sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}} \, dx}{3 b c}+\frac{(4 c) \int \frac{x^2}{\sqrt{1+c^2 x^2} \left (a+b \sinh ^{-1}(c x)\right )^{3/2}} \, dx}{3 b}\\ &=-\frac{2 x \sqrt{1+c^2 x^2}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}+\frac{16 \int \frac{x}{\sqrt{a+b \sinh ^{-1}(c x)}} \, dx}{3 b^2}\\ &=-\frac{2 x \sqrt{1+c^2 x^2}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}+\frac{16 \operatorname{Subst}\left (\int \frac{\cosh (x) \sinh (x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{3 b^2 c^2}\\ &=-\frac{2 x \sqrt{1+c^2 x^2}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}+\frac{16 \operatorname{Subst}\left (\int \frac{\sinh (2 x)}{2 \sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{3 b^2 c^2}\\ &=-\frac{2 x \sqrt{1+c^2 x^2}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}+\frac{8 \operatorname{Subst}\left (\int \frac{\sinh (2 x)}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{3 b^2 c^2}\\ &=-\frac{2 x \sqrt{1+c^2 x^2}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{4 \operatorname{Subst}\left (\int \frac{e^{-2 x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{3 b^2 c^2}+\frac{4 \operatorname{Subst}\left (\int \frac{e^{2 x}}{\sqrt{a+b x}} \, dx,x,\sinh ^{-1}(c x)\right )}{3 b^2 c^2}\\ &=-\frac{2 x \sqrt{1+c^2 x^2}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 \operatorname{Subst}\left (\int e^{\frac{2 a}{b}-\frac{2 x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c x)}\right )}{3 b^3 c^2}+\frac{8 \operatorname{Subst}\left (\int e^{-\frac{2 a}{b}+\frac{2 x^2}{b}} \, dx,x,\sqrt{a+b \sinh ^{-1}(c x)}\right )}{3 b^3 c^2}\\ &=-\frac{2 x \sqrt{1+c^2 x^2}}{3 b c \left (a+b \sinh ^{-1}(c x)\right )^{3/2}}-\frac{4}{3 b^2 c^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{8 x^2}{3 b^2 \sqrt{a+b \sinh ^{-1}(c x)}}-\frac{2 e^{\frac{2 a}{b}} \sqrt{2 \pi } \text{erf}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{3 b^{5/2} c^2}+\frac{2 e^{-\frac{2 a}{b}} \sqrt{2 \pi } \text{erfi}\left (\frac{\sqrt{2} \sqrt{a+b \sinh ^{-1}(c x)}}{\sqrt{b}}\right )}{3 b^{5/2} c^2}\\ \end{align*}
Mathematica [A] time = 0.709698, size = 200, normalized size = 1.09 \[ \frac{e^{-2 \left (\frac{a}{b}+\sinh ^{-1}(c x)\right )} \left (e^{\frac{2 a}{b}} \left (4 \sqrt{2} e^{2 \left (\frac{a}{b}+\sinh ^{-1}(c x)\right )} \sqrt{\frac{a}{b}+\sinh ^{-1}(c x)} \left (a+b \sinh ^{-1}(c x)\right ) \text{Gamma}\left (\frac{1}{2},\frac{2 \left (a+b \sinh ^{-1}(c x)\right )}{b}\right )-4 a e^{4 \sinh ^{-1}(c x)}-4 a-b e^{4 \sinh ^{-1}(c x)}-4 b \left (e^{4 \sinh ^{-1}(c x)}+1\right ) \sinh ^{-1}(c x)+b\right )-4 \sqrt{2} b e^{2 \sinh ^{-1}(c x)} \left (-\frac{a+b \sinh ^{-1}(c x)}{b}\right )^{3/2} \text{Gamma}\left (\frac{1}{2},-\frac{2 \left (a+b \sinh ^{-1}(c x)\right )}{b}\right )\right )}{6 b^2 c^2 \left (a+b \sinh ^{-1}(c x)\right )^{3/2}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.051, size = 0, normalized size = 0. \begin{align*} \int{x \left ( a+b{\it Arcsinh} \left ( cx \right ) \right ) ^{-{\frac{5}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{\left (a + b \operatorname{asinh}{\left (c x \right )}\right )^{\frac{5}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x}{{\left (b \operatorname{arsinh}\left (c x\right ) + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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